If OAD = 9.6 mm, OZD = 7.8 mm, PCW = 0.4 mm, the ICW is:

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Multiple Choice

If OAD = 9.6 mm, OZD = 7.8 mm, PCW = 0.4 mm, the ICW is:

Explanation:
In GP lens geometry, the overall diameter is built from the central optic zone and the curves that surround it on both sides. The relationship is expressed as: OAD = OZD + 2 × (ICW + PCW). Here, the overall diameter (9.6 mm) equals the optic zone diameter (7.8 mm) plus twice the sum of the intermediate curve width and the peripheral curve width. Compute step by step: 9.6 − 7.8 = 1.8. This 1.8 mm represents the total width contributed by both sides of the lens, so divide by 2 to get the combined width on one side: 1.8 / 2 = 0.9. Subtract the peripheral curve width (0.4 mm) to isolate the intermediate curve width: 0.9 − 0.4 = 0.5 mm. Therefore, the ICW is 0.5 mm.

In GP lens geometry, the overall diameter is built from the central optic zone and the curves that surround it on both sides. The relationship is expressed as: OAD = OZD + 2 × (ICW + PCW). Here, the overall diameter (9.6 mm) equals the optic zone diameter (7.8 mm) plus twice the sum of the intermediate curve width and the peripheral curve width.

Compute step by step: 9.6 − 7.8 = 1.8. This 1.8 mm represents the total width contributed by both sides of the lens, so divide by 2 to get the combined width on one side: 1.8 / 2 = 0.9. Subtract the peripheral curve width (0.4 mm) to isolate the intermediate curve width: 0.9 − 0.4 = 0.5 mm. Therefore, the ICW is 0.5 mm.

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